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The molar ratio of $Fe^{2+} to\; Fe^{3+} in\; a\; mixture\; of\; FeSO_4$ and $Fe_2(SO_4)_3$ having equal number of sulphate ion in both ferrous and ferric sulphate is :

$\begin{array}{1 1} 1:2 \\ 3:2 \\ 2:3 \\ 2:1 \end{array} $

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Answer :
If $n_1$ moles of $FeSO_4$ are taken number of moles of $Fe^{+2}$ and $SO_4^{-2}$ are $n_1$ and $n_1$ respectively.

If $n_2$ moles of $Fe_2(SO_4)_3$ are taken number of moles of $Fe^{+3}$ and $SO_4^{–2}$ are $2n_2$ and $3n_2$ respectively.

 
2:3

 

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