Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

The side of a parallelogram are $2 \hat i +4 \hat j -5 \hat k$ and $ \hat i +2 \hat j +3 \hat k$, then the unit vector parallel to one of the diagonals is :

$\begin{array}{1 1} \frac{1}{7} (3 \hat i +6 \hat j -2 \hat k) \\\frac{1}{7} (-3 \hat i +6 \hat j -2 \hat k) \\ \frac{1}{7} (-3 \hat i +6 \hat j +2 \hat k) \\ \frac{1}{7} (3 \hat i +6 \hat j +2 \hat k) \end{array} $

1 Answer

Comment
A)
Let $\overrightarrow{AB} = 2 \hat{i} + 4 \hat{j} -5 \hat{k}$
$\overrightarrow{BC} = \hat{i} + 2 \hat{j} + 3 \hat{k}$
$\therefore \overrightarrow{AC} = \overrightarrow{AB} + \overrightarrow{BC}$
$\; \; \; \; \;= 3 \hat{i} + 6 \hat{j} - 2 \hat{k}$
$|\overrightarrow{AC} | = \sqrt{3^2 + 6^2+(-2)^2} = 7$
$\therefore$ unit vector parallel to $\overrightarrow{AC}$ is $\frac{1}{7} (3 \hat{i} + 6 \hat{j} -2 \hat{k})$
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
...