$\begin{array}{1 1} \frac{1}{7} (3 \hat i +6 \hat j -2 \hat k) \\\frac{1}{7} (-3 \hat i +6 \hat j -2 \hat k) \\ \frac{1}{7} (-3 \hat i +6 \hat j +2 \hat k) \\ \frac{1}{7} (3 \hat i +6 \hat j +2 \hat k) \end{array} $

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