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The threshold frequency of a certain metal is $3.3 \times 10^{14}\;Hz$ . If light of frequency $8.2 \times 10^{14}\;Hz$ is incident on the metal, Predict the cut off voltage for photo electric emission . Given Planck's Constant , $h= 6.62 \times 10^{-34} \;Js$

$\begin{array}{1 1} 20.274 \;v \\ 202.74\;v \\ 2027.4 \;v\\ 2.0274\;v \end{array} $

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