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Home  >>  CBSE XII  >>  Math  >>  Relations and Functions
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Let $\ast$ be the binary operation on $N$ given by $a \ast b =$ LCM of $a$ and $b$. $(iv)$ Find the identity of $\ast$ in $N$.

$\begin{array}{1 1} 0 \\ 1 \\ a \ast b\\ LCM*(a,b)\end{array} $

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Toolbox:
  • The lowest common multiple of two integers a and b, usually denoted by LCM(a, b), is the smallest positive integer that is divisible by both a and b.
Given that the binary operation on N given by $a \ast b = $ LCM $(a,b)$:
To find the identity of $\ast$, we take the LCM $(a,1)$ and LCM $(1,a)$:
LCM $(a,1) = a$ and LCM $(1,a) = a \rightarrow 1$ is the identity of $\ast$ in $N$.
answered Mar 19, 2013 by balaji.thirumalai
 

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