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Questions  >>  Olympiad-Math  >>  Class 10
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Q)

If $ \tan \theta = \large\frac{20}{21}$ then $ \large\frac{\cos \theta - \sin \theta}{\cos \theta +\sin \theta}$

$\begin{array}{1 1}(A) \; \large\frac{1}{41} \\(B)\;\large\frac{1}{20} \\(C)\;\large\frac{1}{21} \\(D)\; \large\frac{1}{20} \end{array}$

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A)
Solution :
Given :$\tan \theta = \large\frac{20}{21} $
Dividing all terms of $\large\frac{\cos \theta - \sin \theta }{\cos \theta +\sin \theta}$ by $\cos \theta$
$\qquad=\large\frac{1- \tan \theta}{1+\tan \theta }$
$\qquad= \large\frac{1- \Large\frac{20}{21}}{1+\Large\frac{20}{21}}$
$\qquad= \large\frac{21-20}{21+20}$
$\qquad= \large\frac{1}{41}$
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