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Questions  >>  Olympiad-Math  >>  Class 10
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Q)

To divide a line segment $LM$ in the ratio $4 : 3$, a ray $LX$ is drawn firs such that $\angle MLX$ is an acute angle and then points $L_1, L_2, L_3, …$ are located at equal distances on the ray $LX$ and the points $M$ is joined to :

$(A) \; L_2 \\(B)\; L_4 \\(C)\; L_7 \\(D)\; L_3$

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A)
Solution :
To divide a line segment $AB$ in the ratio $m : n$, a ray $AX$ is drawn in such that $\angle BAX$ is an acute angle and then points $A1, A2, A3, …….., Am, …….. An$ are located at equal distances on the ray $AX$ and then the point $B$ is joined to $AnB$.
Therefore, according to question, the point $M$ is joined to $L7M$.
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