Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  CBSE XII  >>  Math  >>  Model Papers
Answer
Comment
Share
Q)

Find the length of the perpendicular drawn from the origin to the plane 2X-3Y+6Z+21=0.

This question appeared in 65-1,65-2 and 65-3 versions of the paper in 2013.

1 Answer

Comment
A)
Toolbox:
  • The distance of a point $P(x_1,y_1,z_1)$ from a plane $Ax+BY+CZ+D=0$ is given by $\large \frac{Ax_1+By_1+Cz_1+D}{\sqrt{A^2+B^2+C^2}}$
Given a place $2X+3Y+6Z+21=0$.
The distance of a point $P(x_1,y_1,z_1)$ from a plane $Ax+BY+CZ+D=0$ is given by $\large \frac{Ax_1+By_1+Cz_1+D}{\sqrt{A^2+B^2+C^2}}$
We need to calculate the distance from the origin $P(0,0,0)$ to the place.
$\Rightarrow$ Distance $=\Large \frac{2(0)-3(0)+6(0)+21}{\sqrt{2^2+3^2+6^2}}$
$\Rightarrow$ Distance $=\Large \frac{21}{\sqrt{49}}=\frac{21}{7}\normalsize =3\;$ units.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...