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Home  >>  CBSE XII  >>  Math  >>  Differential Equations
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Determine order and degree (if defined) of differential equation\[\bigg(\frac{ds}{dt}\bigg)^4 +3s\frac{d^2s}{dt^2}=0\]

$\begin{array}{1 1}order2, degree1 \\order1, degree2 \\ order1, degree1 \\order1, degree2 \end{array} $

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1 Answer

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  • The highest order derivative present in the differential equation determines the order of the equation.The power to which this derivative is raised determines the degree of the equation.
Step 1:
The highest order derivative present in the differential equation is $\large\frac{d^2s}{dt^2}$.So the order is 2.
Step 2:
It is a polynomial equation in $s''$ and the highest power raised to $\large\frac{d^2s}{dt^2}$ is 1,so the degree is 1.
answered Jul 29, 2013 by sreemathi.v
 

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