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Questions  >>  CBSE XII  >>  Physics  >>  Electromagnetic waves
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Q)

One requires $11\;ev$ of energy to dissociate a carbon monoxide molecule into carbon and oxygen atoms. The minimum frequency of the appropriate electromagnetic radiation to achieve dissociation lies in

$\begin{array}{1 1} \text{Visible region } \\ \text{infrared region} \\ \text{ultra violet region} \\ \text{micro wave region} \end{array} $

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A)
Solution :
$E= 11ev= 11 \times 1.6 \times 10^{-9}$
$\alpha = \large\frac{11 \times 1.6 \times 10^{-19}}{6.62 \times 10^{-34}}$
$\qquad=2.65 \times 10^{15}\;Hz$
The belongs to ultra violet region .
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