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Home  >>  CBSE XII  >>  Math  >>  Differential Equations
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Determine order and degree (if defined) of differential equation$\bigg(\large\frac{d^2y}{dx^2}\bigg)^2+\normalsize \cos\bigg(\large\frac{dy}{dx}\bigg)=0$

$\begin{array}{1 1}order4, degree\;not\;defined \\order3, degree\;not\;defined \\ order1, degree\;not\;defined \\order2, degree\; not\; defined \end{array} $

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1 Answer

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Toolbox:
  • The highest order derivative present in the differential equation determines the order of the equation.The power to which this derivative is raised determines the degree of the equation.
Step 1:
The highest order derivative present in the differential equation is $\large\frac{d^2y}{dx^2}$,so its order is 2.
Step 2:
It is not a polynomial equation in its derivatives.So its degree is not defined.
answered Jul 29, 2013 by sreemathi.v
 
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