Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  CBSE XII  >>  Physics  >>  Electromagnetic waves
Answer
Comment
Share
Q)

The ratio of contribution made by the electric and magnetic field components to the intensity of an EM wave is

$\begin{array}{1 1} c:1 \\ c^2:1 \\ 1:1 \\ \sqrt c:1 \end{array} $

1 Answer

Comment
A)
Solution :
Intensity of em wave $I= U_{av}c$
$U_{av}= \large\frac{1}{2} \frac{B_0^2}{M_0^2}$
$U_{av}$ (electric field) $= \large\frac{1}{2} \in_0$$ (c B_0)^2$
$\qquad= \large\frac{1}{2} $$\in_0 \large\frac{1}{\mu_0 \in _0}$$B_0^2$
$\qquad= \large\frac{1}{2} \frac{B_0^2}{\mu_0}$
$\qquad= U_{ar}$ (magnetic field)
This proves that in $em$ wave is divided equally between electric field vector and magnetic field vector .
Hence the ratio of contribution is $1:1$
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...