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Questions  >>  CBSE XII  >>  Physics  >>  Electromagnetic waves
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A changed particle oscillates about its means equilibrium position with a frequency of $10^9$ Hz. The electromagnetic wave produced

$\begin{array}{1 1} \text{will have frequency of } 10^9 Hz \\ \text{will have frequency of } 2 \times 10^9 Hz \\ \text{will have a wave length of } 0.3\;m \\ \text{fall in the region of radio waves} \end{array} $

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A)
Solution :
$\gamma = 10^9 \;Hz$
$\lambda= \large\frac{c}{\alpha}$
$\qquad= \large\frac{3 \times 10^8}{10^9}$
$\qquad= 0.3 \;m$
This falls in the region of radio waves.
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