Comment
Share
Q)

# A variable frequency a.c source is connected to a capacitor .How will the displacement current change with decrease in frequency ?

$\begin{array}{1 1} \text{As conduction current decreases , frequency decreases } \\ \text{As conduction current increases , frequency decreases } \\ \text{There will be no charge} \\ \text{As conduction current decreases , frequency decreases initially and then increases }\end{array}$

Current through the capacitor is $I= \large\frac{E}{X_c}$
$\qquad= \large\frac{E}{1/Cw}$
$\quad = ECw$
$\qquad= 2 \pi \alpha CE$
$I \alpha \gamma$
Hence decrease in the frequency $\alpha$ of a.c . source decrease the conduction current .