A box contains 2 red and 3 blue balls. Two balls are drawn successively without replacement. If getting 'a red ball on first draw and a blue ball on second draw' is considered a success, then find the probability of 2 successes in 3 performances.
I tried to find the value of p by (2C1x3C1)/5C2 but this is not correct, according to the answer key. What mistake have I made?
