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# In an a.c circuit , there is no power consumption in an ideal inductor . why ?

$\begin{array}{1 1} phase \;angle\; \phi =zero \\ phase \;angle\; \phi =90^{\circ} \\ phase \;angle\; \phi = 45^{\circ} \\ \text{none of the above }\end{array}$

$P= E_vI_v \cos \phi$
In an ideal indicator , which has no ohmic resistance , phase angle $\phi =90^{\circ}$
$\therefore P= E_v I_v \cos 90^{\circ}=zero$
Answer : $phase \;angle\; \phi =90^{\circ}$