Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  CBSE XII  >>  Physics  >>  Alternating current
Answer
Comment
Share
Q)

In a series LCR circuit , the voltage across an inductor, a capacitor and a resistor are $30\;v, 30\;v$ and $60\;v$ respectively . What is the phase difference between the applied voltage and the current in the circuit .

$\begin{array}{1 1} \phi = 90^{\circ} \\ \phi = 45^{\circ} \\ \phi = 180^{\circ} \\ \phi = zero\end{array} $

1 Answer

Comment
A)
Solution :
Let $\phi$ be the phase difference betweeen applied voltage and the current
$\tan \phi = \large\frac{X_L- X_C}{R}$
$\qquad= I_v \large\frac{(X_L-X_C)}{I_vR}$
$\qquad= \large\frac{V_L -V_C}{V_R}$
$\qquad= \large\frac{30-30}{60}$
$\tan \phi = zero$
$\phi = 0^{\circ}$
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...