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CBSE XII
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Vector Algebra
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Find the vector and Cartesian equation of the line through the point (5, 2, -4) and which is parallel to the vector $3 \hat{i} +2 \hat{j} -8 \hat{k}$
$(A)\; \frac{x-5}{3} = \frac{y-2}{2} = \frac{z+4}{-8}$
$(B)\; \frac{x-5}{3} = \frac{y+2}{2} = \frac{z+4}{-8}$
$(C)\; \frac{x+5}{3} = \frac{y-2}{2} = \frac{z+4}{-8}$
$(D)\; \frac{x+5}{3} = \frac{y+2}{2} = \frac{z+4}{-8}$
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