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# Two eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is at least one defective egg.

$(A)\; \frac{9}{10}$
$(B)\; (\frac{9}{10})^{10}$
$(C)\; 1-(\frac{9}{10})^{10}$
$(D)\; 1+(\frac{9}{10})^{10}$

$n = 10 \;and \; \; \; \; P= \frac{10}{100} = \frac{1}{10} \implies q = \frac{1}{10}$
P (at least one defective egg) = $P (x \geq 1 )$
$= 1 - P (x =10)$
$=1-10C_0(\frac{9}{10})^{10}$
$= 1 - (\frac{9}{10})^{10}$