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Q)

Let $\ast \; R \times R \to R$ given by $(a,b) \to a + 4b^2$ is a binary operation, compute $-5 \ast (2 \ast 0).$

(A) 11
(B) 10
(C) 9
(D) 0

$\ast \; R \times R \to R$
$a \ast b = a + 4b^2$
\begin{align*}\implies -5 \ast (2 \ast 0) & =(-5) \ast [2 + 4 (0)^2] \\ & = -5 \ast 2 \\& = -5 + 4(2)^2 \\ & = -5 + 4 \times 4 \\ & = 11 \end{align*}