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Determine order and degree (if defined) of differential equation $y''+(y')^2+2y=0$

$\begin{array}{1 1}order2, degree1 \\order1, degree2 \\ order1, degree1 \\order2, degree2 \end{array} $

1 Answer

Toolbox:
  • The highest order derivative present in the differential equation determines its order.The highest power raise to the derivative determines its degree.
Step 1:
The highest order present in the differential equation is $\large\frac{d^2y}{dx^2}$.Hence the order is 2.
Step 2:
It is a polynomial equation in $y''$ and the highest power raised to $\large\frac{d^2y}{dx^2}$ is 1.So the degree is 1.
answered Jul 29, 2013 by sreemathi.v
 
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