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The number of silicon atoms per $m^3$ is $5 \times 10^{28}$ This is doped simultaneously with $5 \times 10^{22}$ atom per $m^3$ of and $5 \times 10^{26}$ per $m^3$ atoms of indium . Calculate the number of electrons and holes . Given that $n_i=1.5 \times 10^{16}\;m^{-3}$. material n -type or p type

$\begin{array}{1 1} 4.54 \times 10^{10} m^{-3} \\ 4.54 \times 10^{10} m^{3} \\ 4.54 \times 10^{9} m^{3} \\ 4.54 \times 10^{9} m^{-3}\end{array}$

$n_e= 5 \times 10^{22}- 5 \times 10^{20}$
$\qquad= 4.95 \times 10^{22} m^{-3}$
$n_h= \large\frac{n_i^2}{n_e}$
$\qquad= \large\frac{(1.5 \times 10^{9})}{(4.95 \times 10^{22})}$
$\qquad= 4.54 \times 10^{9} m^{-3}$