Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

The number of silicon atoms per $m^3$ is $5 \times 10^{28}$ This is doped simultaneously with $ 5 \times 10^{22}$ atom per $m^3$ of and $ 5 \times 10^{26}$ per $m^3 $ atoms of indium . Calculate the number of electrons and holes . Given that $n_i=1.5 \times 10^{16}\;m^{-3}$. material n -type or p type

$\begin{array}{1 1} 4.54 \times 10^{10} m^{-3} \\ 4.54 \times 10^{10} m^{3} \\ 4.54 \times 10^{9} m^{3} \\ 4.54 \times 10^{9} m^{-3}\end{array} $

1 Answer

Comment
A)
Solution :
$n_e= 5 \times 10^{22}- 5 \times 10^{20}$
$\qquad= 4.95 \times 10^{22} m^{-3}$
$n_h= \large\frac{n_i^2}{n_e}$
$\qquad= \large\frac{(1.5 \times 10^{9})}{(4.95 \times 10^{22})}$
$\qquad= 4.54 \times 10^{9} m^{-3}$
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...