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Q)

The voltage gain of an amplifier with $9\%$ negative feed back is $10$. The voltage gain with out feedback will be

$\begin{array}{1 1} 90 \\ 10 \\ 1.25 \\ 100 \end{array} $

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A)
Solution :
$A_{fb}=10$
$m=9\%$
$A_{fb}=\large\frac{A}{1+A m}$
(ie) $10 = \large\frac{A}{1+A.\large\frac{9}{100}}$
$A=100$
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