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Q)

In the circuit given below , when the input voltage of the base resistance is $10\;V,V_{BE}$ is zero. and $V_{CE}$ is also zero. Find the value of $I_c$ and $\beta$

$\begin{array}{1 1} I_c=33.3\;mA, \;\beta =13.3 \\ I_c=3.33\;mA, \;\beta =133 \\ I_c=3.33\;mA, \;\beta =1.33 \\ I_c=333\;mA, \;\beta =133 \end{array} $

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A)
Solution :
$V_{CC}-V_{CE}= I_CR_C$
$10-0 = I_C \times (3 \times 10^4)$
$\therefore I_c= \large\frac{10}{3 \times 10^4}$$=3.33 \times 10^{-3}\;A$
$\qquad= 3.33\;mA$
$\beta = \large\frac{I_c}{I_b}= \frac{3.33 \times 10^{-3}}{25 \times 10^{-6}}$$=133$
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