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# Truth table for the given circuit is

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A)
Solution :
$C=A.B$ and $D= \bar{A}.B$
$E= C+D=(A.B)+(\bar {A}.B)$
Hence the truth table is as follows

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C=AB  & D=A'B

E=C+D=AB+A'B=B(A+A')=B

SO THE OUTPUT IS SAME AS B.