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Three capacitors of capacitances $2pF, 3pF$ and $4pF$ are connected in parallel. What is the total capacitance of the combination?

$\begin{array}{1 1} 9\;pF \\ 6\;pF \\ 4\;pF \\ 2\;pF \end{array} $

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Solution :
Capacitances of the given capacitors: $C_1 = 2 pF, C_2 = 3 pF$ and $C_3 = 4 pF$ For the parallel combination of the capacitors, equivalent capacitor is given by $C_{eq}$ the algebraic sum,
Therefore $C_{eq} =C_1+C_2+C_3=2+3+4=9\;F$
Therefore , total capacitance of the combination is 9pF
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