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A spherical conductor of radius $12\; cm$ has a charge of $1.6 \times 10^{−7}\;C$ distributed uniformly on its surface. What is the electric field at a point 18 cm from the center of the sphere ?

$\begin{array}{1 1} 4 \times 10^{4}NC^{-1} \\ 4.4 \times 10^{4}NC^{-1} \\ 0.4 \times 10^{4}NC^{-1}\\ 5 \times 10^{4}NC^{-1}\end{array} $

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A)
Solution
Electric field at a point 18 m from the centre of the sphere =$ E_1$
Distance of the point from the centre , $d= 18\;cm =0.18\;m$
$E_1= \large\frac{1}{4 \pi \in_0}. \frac{q}{d^2}$
$\qquad= \large\frac{9 \times 10^9 \times 1.6 \times 10^{-7}}{(1.8 \times 10^{-2})^2}$
$\qquad= 4.4 \times 10^4 \;NC^{-1}$
Therefore, the electric field at a point 18 cm from the centre of the sphere is $4.4 \times 10^4 NC ^{-1}$
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