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Three capacitors each of capacitance $9 \;pF$ are connected in series. What is the potential difference across each capacitor if the combination is connected to a $120\; V$ supply?

$\begin{array}{1 1} 40V \\ 56V \\ 67V \\ 56V \end{array} $

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A)
Solution :
Supply voltage, V = 100 V
Potential difference (V1) across each capacitor is equal to one-third of the supply voltage
$V_1= \large\frac{V}{3}=\frac{120}{3}=40\;V$
Therefore, the potential difference across each capacitor is 40 V.
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