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Find the projection of $\overrightarrow{i}-\overrightarrow{j}$ on $z$ axis

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  • For any two vectors $ \overrightarrow a \: and \overrightarrow b$, the projection of $\overrightarrow a \: on \: \overrightarrow b= \large\frac{\overrightarrow a.\overrightarrow b}{|\overrightarrow b|}$
$ \overrightarrow a = \overrightarrow i-\overrightarrow j$. Its projection along the $z$ axis is the projection along $ \overrightarrow k$
Projection of $ \overrightarrow a\: on \: \overrightarrow k = \large\frac{\overrightarrow a.\overrightarrow k}{|\overrightarrow k|}=0$
( Since $ \overrightarrow i.\overrightarrow k = \overrightarrow j.\overrightarrow k=0)$
answered Jun 2, 2013 by thanvigandhi_1

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