$\begin{array}{1 1}(1) 1:16 \\ (2) 4:1 \\(3) 1:4 \\ (4) 5:4 \end{array} $

Solution :

80 minutes = 4 half-lives of A = 2 half-lives of B

Let the initial number of nuclei in each sample be N

$N_A$ after 80 minutes $= \large\frac{N}{2^4}$

=> Number of A nuclides decayed $=\large\frac{15}{16} $$N$

$N_B$ after 80 minutes $= \large\frac{N}{2^4}$

=> Number of B nuclides decayed $=\large\frac{3}{4} $$N$

Required ratio $= \Large\frac{15/16}{3/4}$

$\qquad= \large\frac{5}{4}$

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