The reaction of propene with $HOCl(Cl_2 + H_2O)$ proceeds through the intermediate :

Question

$\begin{array}{1 1} (1) CH_3 -CH^{+} -CH_2 -OH \\ (2)CH_3-CH^{+}-CH_2-Cl \\ (3)CH_3-CH(OH)-CH_2^{+} \\ (4)\; CH_3-CHCl-CH^{+}_2 \end{array} $