logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XII  >>  Math  >>  Differential Equations
0 votes

The general solution of a differential equation of the type $\large\frac{dx}{dy}$$+p_1x=Q_1\;is$

\[ \begin{array}{l} (A)\quad y\;\mathrm{e}^{\int p_1\mathrm{d}y}=\int\bigg(Q_1\mathrm{e}^{\int p_1\mathrm{d}y}\bigg)dy+C \\ (B)\quad y\;.\mathrm{e}^{\int p_1\mathrm{d}x}=\int \bigg(Q_1\mathrm{e}^{\int p_1\mathrm{d}x}\bigg)dx+C \\ (C)\quad x\;\mathrm{e}^{\int p_1\mathrm{d}y}=\int \bigg(Q_1\mathrm{e}^{\int p_1dy}\bigg)dy+C \\ (D)\quad x\;\mathrm{e}^{\int p_1dx}=\int\bigg(Q_1\mathrm{e}^{\int p_1\mathrm{d}x}\bigg)dx+C \end{array} \]

Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • If the first order linear equation is of the type $\large\frac{dx}{dy}$$+px=Q$,then the solution is x( I.F) = integration Q.(I.F) + C where I.F =$ e^{\int p dy}$
Using the information in the tool box we find that the given equation is of the form $\large\frac{dx}{dy} $$+ Px = Q$
Hence the solution is x(I.F) = integration of Q.(I.F) dx + C
Here the integral factor is $\int pdy$
Hence C is the correct answer.
answered Jul 29, 2013 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...