Given : $E^0_{Cr^{3+}/Cr} =-0.74\;V ; E^0_{MnO^{-}_4/Mn^{2+}}=1.51\;V $$E^0_{Cr_2O^{2-}_7/Cr^{3+}} =-1.33\;V ; E^0_{Cl/Cl^{-}}=1.36\;V $ Based on the data given above, strongest oxidising agent will be :

Question

$\begin{array}{1 1} (1) Cl^{-} \\ (2) Cr^{3+} \\ (3) Mn^{2+} \\ (4) MnO^{-}_4 \end {array}$