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Consider : Statement − I : $(p \wedge \sim q) \wedge p ( \sim p \wedge q)$ is fallacy. Statement - II : $(p \to q) \longleftrightarrow ( \sim q \to \sim p)$ is a tautology

$\begin{array}{1 1} \text{(1) Statement − I is true; Statement − II is true; Statement − II is a correct explanation for Statement I.} \\ \text{(2) Statement − I is true; Statement − II is true; Statement − II is not a correct explanation for Statement − I} \\ \text{(3) Statement − I is true; Statement − II is false. } \\ \text{(4) Statement − I is false; Statement − II is true. } \end {array}$

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