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Sodium metal crystallises in body centred cubic lattice with cell edge 4.29

Sodium metal crystallises in body centred cubic lattice with cell edge 4.29Å. What is the radius of sodium atom?
Please say what's the answer?

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Solution :
In a body centered cubic lattice, atoms touch along the body diagonal of the cube . Thus
$4r= \sqrt 3 a$
or $r= \large\frac{\sqrt{3}}{4} $$a$
$\qquad= \bigg(\large\frac{\sqrt 3}{4} \bigg)$$(4.29 \dot{A})=1.86 \dot{A}$
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