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Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to $A$ and $T$, respectively. At time $t=0$ one particle has displacement $A$ while the other one has displacement $\large\frac{−A}{2}$ and they are moving towards each other. If they cross each other at time t, then t is :

$\begin{array}{1 1}(1) \large\frac{T}{4} \\ (2) \large\frac{5T}{6} \\ (3) \large\frac{T}{3} \\ (4) \large\frac{T}{6} \end{array} $

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