# Find the equation of the curve passing through the point$$\bigg(0,\large\frac{\pi}{4}\bigg)$$ whose differential equation is $\sin x\cos y\;dx+\cos x\sin y\;dy\;=\;0$

Toolbox:
• A linear differential equation of the form dy/dx = F(x,y) where F(x,y) is of the form g(x).h(y) where g(x) is a fuunction of x and h(y) is a function of y, then this type of equation is called as variables seperable and the equation can be solved by seperating the variables.
Step 1:
Given :$\sin x\cos ydx+\cos x\sin ydy=0$
We can write above equation as
$\large\frac{dy}{dx} = -\large\frac{ (\sin x\cos y)}{(\cos x\sin y)}$
Using the information in the tool box, we understand that the given equation is variable seperable and it can be solved by seperating the variables.
Seperating the variables we get,
$\large\frac{\sin ydy}{\cos y }= -\large\frac{ \sin xdx}{\cos x}$
$\tan y dy=-\tan xdx$
Integrating on both sides we get,
$\int\tan y=-\int \tan x$
$\log\mid\sec y\mid=-\log\mid\sec x\mid+\log C$
$\log C=\log\mid\sec y\mid+\log\mid \sec x\mid$
$\log C=\log\mid\sec y.\sec x\mid$
$C=\sec y.\sec x$
Step 3:
Substituting the given values of x = 0 and $y = \pi/4$ to evaluate the value of C