$\begin{array}{1 1}(1)\; \frac{∆Y}{Y} \;gets \;minimum \;contribution\; from \;the \;uncertainty \;in \;the \;length. \\(2)\; The \;figure \;of \;merit \;is \;the \;largest \;for \;the \;length \;of \;the \;rod. \\(3)\; The \; maximum\; value\; of\; Y\; that\; can\; be\; determined\; is\; 10^{14} N/m^2. \\ (4)\; \frac{\Delta Y}{Y} gets\; its\; maximum\; contribution\; from\; the\; uncertainty\; in \; strain. \end{array} $