If $P=\begin{bmatrix} \large\frac{\sqrt 3}{2} & \frac{1}{2} \\ \large\frac{-1}{2} & \large\frac{\sqrt 3}{2} \end{bmatrix} $ , $A=\begin{bmatrix} 1 & 1 \\ 0 & 1 \end{bmatrix} $ and $Q= PAP^{T}$, then $P^Tq^{2015}P$ is :

Question

$\begin{array}{1 1} (1) \begin{bmatrix} 0 & 2015 \\ 0 & 0 \end{bmatrix} \\ (2)\begin{bmatrix} 2015 & 1 \\ 0 & 2015 \end{bmatrix}\\ (3) \begin{bmatrix} 2015 & 0 \\ 1 & 2015 \end{bmatrix}\\ (4) \begin{bmatrix} 1 & 2015 \\ 0 & 1 \end{bmatrix}\end{array} $