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Let $P = \{ \theta : \sin \theta - \cos \theta = \sqrt 2 \cos \theta \}$ and $Q = \{ \theta : \sin \theta + \cos \theta = \sqrt 2 \sin \theta $ be two sets. Then :

$\begin{array}{1 1}(1)\; P ⊂ Q \; and \; Q−P \neq \phi \\ (2)\; Q ⊄ P \\ (3)\; P ⊄ Q \\ (4)\; P = Q \end{array} $

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