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Home  >>  TN XII Math  >>  Vector Algebra
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What are the d . c . s of the vector equally inclined to the axes?

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  • If $ l, m , n$ are the d.c.s of a vector, then $ l^2+m^2+n^2=1$
Let $ l, m, n$ be the D.c.s of a vector that is equally inclined to the axes.
$ \therefore \: l = m = n$
$ l^2+m^2+n^2=1 \Rightarrow 3l^2=1\: \: or \: l= \pm \large\frac{1}{\sqrt 3}$
$ \therefore $ the D.c.s are $ \large\frac{1}{\sqrt 3}, \large\frac{1}{\sqrt 3}, \large\frac{1}{\sqrt 3}\: or \: -\large\frac{1}{\sqrt 3}, -\large\frac{1}{\sqrt 3}, -\large\frac{1}{\sqrt 3}$

 

answered Jun 11, 2013 by thanvigandhi_1
edited Jun 24, 2013 by thanvigandhi_1
 

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