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A word consists of 9 different alphabets,in which there are 4 consonants and 5 vowels.Three alphabets are chosen at random .What is the probability that more than one vowel will be selected?

This question has multiple parts. Therefore each part has been answered as a separate question on Clay6.com
Please send the detail of how to do the sum
More than 1 means vowels will be 2 or 3
Then, with the help of Permutations and combination we can easily solve this,
Here, selection of vowels are as follow 5c2 * 4c1 + 5c3 * 4c0 = 50
And the total no of selections are 9c3 =84
So probability is =  25/42

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