Step 1:
$\large\frac{y^2}{9}-\large\frac{x^2}{25}$$=1$
$a^2=9,b^2=25$
$a=4,b=5$ and $x$-axis is the transverse axis.
Step 2:
Eccentricity $e=\sqrt{1+\large\frac{b^2}{a^2}}$
$\Rightarrow \sqrt{1+\large\frac{25}{9}}=\large\frac{\sqrt{34}}{3}$
Step 3:
Centre : Origin $O(0,0)$
Step 4:
Foci : $(0,\pm ae)$
$ae=3\times \large\frac{\sqrt{34}}{3}=$$\sqrt{34}$
$\Rightarrow (0,\pm\sqrt{34})$
Vertices : $(0,\pm a)$
$\Rightarrow (0,\pm 3)$