Magnetic field in a plane electromagnetic wave is given by $\overrightarrow{B} =B_0 \sin (kx+ \omega t) \hat j T$ Expression for corresponding electric field will be : Where c is speed of light.

Question

$\begin{array}{1 1} (1)\;\overrightarrow{E} = B_0 c \sin (kx+\omega t ) \hat k V/m \\ (2)\;\overrightarrow{E} =\frac{B_0}{ c} \sin (kx+\omega t ) \hat k V/m \\ (3)\;\overrightarrow{E} =-B_0 c \sin (kx+\omega t ) \hat k V/m \\ (4)\;\overrightarrow{E} = B_0 c \sin (kx+\omega t ) \hat k V/m \end{array} $