Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Find the equation of the asymptotes of the following rectangular hyperbola $2xy+3x+4y+1=0$

Can you answer this question?

1 Answer

0 votes
  • http://clay6.com/mpaimg/3_toolbox%2021.jpg
  • For the standard rectangular hyperbola,the coordinate axes are taken to the asymptotes and the equation of the hyperbola is $xy=c^2$ .
  • If the centre is at $(h,k)$ with asymptotes parallel to the coordinate axes,the equation is $(x-h)(y-k)=c^2$
Step 1:
The above equation is divided by $2$ we get,
Step 2:
Now we take the LHS of the above equation
$\Rightarrow (x+2)(y+\large\frac{3}{2})-\large\frac{5}{2}$$=0$
Step 3:
Since the equation is in standard form,the equations of the asymptotes are $x+2=0,y+\large\frac{3}{2}$$=0$
answered Jun 25, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App