Step 1:
Let the equation of the rectangular hyperbola be $xy=c^2$ and let $P(x_1,y_1)$ be any point on it.
Therefore $x_1y_1=c^2$
The tangent at $P$ is $\large\frac{1}{2}$$(xy_1+yx_1)=c^2$
(i.e) $xy_1+yx_1=2c^2$
Step 3:
It intersects the $x$ and $y$-axes at $A$ and $B$ respectively.
The $x$-coordinates of $A$ and $y$-coordinates of $B$ are obtained by $y=0$ and $x=0$ in the equation of the tangent.$A$ and $B$ are the points $A(\large\frac{2c^2}{y_1},$$0),B(0,\large\frac{2c^2}{x_1})$
Step 4:
Now $OA=\large\frac{2c^2}{y_1},$$OB=\large\frac{2c^2}{x_1}$ and $\Delta AOB$ is rightangled at $O$.
Its area=$\large\frac{1}{2}$$OA\times OB$
$\qquad\;\;=\large\frac{1}{2}$$\times\large\frac{2c^2}{y_1}\times $$\large\frac{2c^2}{x_1}$
$\Rightarrow \large\frac{2c^4}{x_1y_1}$
We know that $x_1y_1=c^2$
$\Rightarrow \large\frac{2c^4}{c^2}$
$\Rightarrow 2c^2$
Therefore the area of the $\Delta$ formed is a constant.