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Find the equation of the line passing through the intersection of the straight lines $2x+3y=1$ and $3x+4y=6$ and perpendicular to the line $5x-2y=7$.
This question has multiple parts. Therefore each part has been answered as a separate question on Clay6.com
isc
class12
modelpaper
2007
sec-a
q1
q1-2
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Apr 16, 2013
by
sreemathi.v
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The equation of the straight line perpendicular to $5x-2y=7$ and passing through the point of intersection of the lines $2x+3y=1$ and $3x+4y=6$ is :
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A straight line is parallel to the x-axis and passes through the intersection of the lines $x+2y+1=0$ and $y=x+7$.Find the equation of the straight line.
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A straight line $y=mx$ passes through the intersection of the straight lines $x+2y-1=0$ and $2x-y+3=0.$Find the value of m.
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The lines $x-2y+6=0$ and $2x-y-10=0$ intersect at the point A.Find the equation of the line making an angle $45^{\circ}$ with the positive direction of the x-axis and passing through the point A.
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The directrix of a conic section is $3x+4y=1$ and focus is (2,3).Find the equation of the conic section if its eccentricity is $\large\frac{1}{\sqrt 2}$
asked
Apr 18, 2013
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Find the equation of a plane through the point (-1,-1,2) and perpendicular to the planes $3x+2y-3z=1$ and $5x-4y+z=5.$
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part-2
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