If x, y, z are nonzero real numbers, then the inverse of matrix A = $\begin{bmatrix} x & 0 & 0 \\ 0 & y & 0 \\ 0 & 0 & z \end{bmatrix}$ is

Question

$\begin{array}{l \hspace{40 mm} l} (A) \, \begin{bmatrix} x^{-1} & 0 & 0 \\ 0 & y^{-1} & 0 \\ 0 & 0 & z^{-1} \end{bmatrix}\; \quad& (B)\, xyz \,\begin{bmatrix} x^{-1} & 0&0 \\ 0& y^{-1} &0 \\ 0 & 0 & z^{-1} \end{bmatrix} \\[1em] (C) \, \frac{1}{xyz} \,\begin{bmatrix} x & 0 & 0 \\ 0 & y & 0 \\ 0 & 0 & z \end{bmatrix} \quad & (D)\, \frac{1}{xyz} \,\begin{bmatrix} 1 & 0&0 \\ 0& 1 &0 \\ 0 & 0 & 1 \end{bmatrix} \end{array} $