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# Figure shows a circuit that contains three identical resistors with resistance R=9.0 O each, two identical inductors with inductance L=2.0 mH each, and an ideal battery with emf e: 18 V. The current 'i' through the battery just after the switch closed is,.....

$\begin{array}{1 1} (1) 2\;mA \\ (2) 0.2\;A \\ (3) 2\;A \\ (4) 0 \;ampere \end{array}$

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Inductor act as a open circuit. Thus equivalent resistance =9ohm. Therefore ,I=E/R =18/9 =2A