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The overall percentage of passes in a certain examination is $80$.If $6$ candidates appear in the examination what is the probability that atleast $5$ pass the examination.

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  • A random variable $X$ is said to follow a binomial distribution of its probability mass function is given by
  • $P(X=x)=p(x)=\left\{\begin{array}{1 1}nC_xp^xq^{n-x},&x=0,1.......n\\0,&otherwise\end{array}\right.$
  • Constants of Binomial Distribution :
  • Mean = np
  • Variance = npq
  • Standard deviation =$\sqrt{ variance }=\sqrt{ npq}$
  • In a bionomial distribution Mean > Variance.
  • The parameters of the distribution are $n,p\quad X\sim B(n,p)$
Step 1:
Let $X$ be the random variable denoting the number of students that pass in an exam out of a total of 6 students.
Probability that a student will pass =$\large\frac{80}{100}=$$0.8=p$
$X\sim B(6,0.8)$ and $q=1-0.8=0.2$
Step 2:
The probability distribution $X$ is given by
$P(X=x)=6C_x(0.8)^x(0.2)^{6-x}\qquad x=0,1,2......6$
Step 3:
Probability that at least 5 pass in the exam =$P(X\geq 5)=P(X=5)+P(X=6)$
$\qquad\qquad\qquad\qquad\qquad\qquad\qquad=(0.8)^5\times 2$
answered Sep 18, 2013 by sreemathi.v

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