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TN XII Math
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Probability Distribution
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If $Z$ is a standard normal variate. Find the value of $c$ for the following $P(Z > c)=0.85$
tnstate
class12
bookproblem
ch10
sec-1
exercise10-5
p228
q2
q2-3
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asked
Apr 22, 2013
by
poojasapani_1
edited
Sep 19, 2013
by
sreemathi.v
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1 Answer
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Toolbox:
Standard normal distribution:
In a standard normal distribution $\mu=0,\sigma ^2=1$
The random variable $X$ can be converted to the standard normal variable $Z$ by the transformation
$Z=\large\frac{X-\mu}{\sigma}$
http://clay6.com/mpaimg/10.5_q2(3).jpg
$P(Z > c)=0.85$
Since the area > 0.5,the value of c is -ve.
$\therefore P(c < Z < 0)=P(0 < Z < -c)=0.35$
From the table ,
$-c=1.04$
$\Rightarrow c=-1.04$
answered
Sep 19, 2013
by
sreemathi.v
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